7r^2+12r+8=(10+7r-r^2)+(-6r^2-18+5r)

Solution for 7r^2+12r+8=(10+7r-r^2)+(-6r^2-18+5r) equation:

7r^2+12r+8=(10+7r-r^2)+(-6r^2-18+5r)

We move all terms to the left:

7r^2+12r+8-((10+7r-r^2)+(-6r^2-18+5r))=0


We calculate terms in parentheses: -((10+7r-r^2)+(-6r^2-18+5r)), so:

(10+7r-r^2)+(-6r^2-18+5r)

We get rid of parentheses

-r^2-6r^2+7r+5r+10-18

We add all the numbers together, and all the variables

-7r^2+12r-8

Back to the equation:

-(-7r^2+12r-8)


We get rid of parentheses

7r^2+7r^2-12r+12r+8+8=0

We add all the numbers together, and all the variables

14r^2+16=0

a = 14; b = 0; c = +16;
Δ = b2-4ac
Δ = 02-4·14·16
Δ = -896
Delta is less than zero, so there is no solution for the equation